24806.25-25y^2-350y=0

Solution for 24806.25-25y^2-350y=0 equation:

24806.25-25y^2-350y=0

a = -25; b = -350; c = +24806.25;
Δ = b2-4ac
Δ = -3502-4·(-25)·24806.25
Δ = 2603125
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2603125}=\sqrt{30625*85}=\sqrt{30625}*\sqrt{85}=175\sqrt{85}$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-350)-175\sqrt{85}}{2*-25}=\frac{350-175\sqrt{85}}{-50}
$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-350)+175\sqrt{85}}{2*-25}=\frac{350+175\sqrt{85}}{-50}
$